-16x^2+5x+105=45

Solution for -16x^2+5x+105=45 equation:

-16x^2+5x+105=45

We move all terms to the left:

-16x^2+5x+105-(45)=0

We add all the numbers together, and all the variables

-16x^2+5x+60=0

a = -16; b = 5; c = +60;
Δ = b2-4ac
Δ = 52-4·(-16)·60
Δ = 3865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{3865}}{2*-16}=\frac{-5-\sqrt{3865}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{3865}}{2*-16}=\frac{-5+\sqrt{3865}}{-32}
$